What is the answer to log_{10}(x^2-x-6)-x=log_{0}(n+8)-4(2) ?

The answer to log_{10}(x^2-x-6)-x=log_{0}(n+8)-4(2) is No Solution for x\in\mathbb{R}

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log_{10}(x^2-x-6)-x=log_{0}(n+8)-4(2)

lo g_{10} (x^{2} - x - 6) - x = lo g_{0} (n + 8) - 4 (2)

No Solution for x \in R

Solution steps

lo g_{10} (x^{2} - x - 6) - x = lo g_{0} (n + 8) - 4 (2)

Multiply the numbers:

4 \cdot 2 = 8

lo g_{10} (x^{2} - x - 6) - x = lo g_{0} (n + 8) - 8

Move

x

to the right side

lo g_{10} (x^{2} - x - 6) = lo g_{0} (n + 8) - 8 + x

Simplify

lo g_{0} (n + 8) - 8 + x :

Undefined

lo g_{10} (x^{2} - x - 6) = Undefined

Apply log rules

x^{2} - x - 6 = 1 0^{Undefined}

Solve

x^{2} - x - 6 = 1 0^{Undefined} :

No Solution for

x \in R

No Solution for x \in R

lo g_{2} (a^{2} - 5) = 2

lo g_{x} (20) + lo g_{x} (5) = 2

lo g_{3} (lo g_{2} (x + 9)) = 1

ln (x^{2}) = 2 ln (x)

lo g_{16} (x) = \frac{3}{4}

What is the answer to log_{10}(x^2-x-6)-x=log_{0}(n+8)-4(2) ?
The answer to log_{10}(x^2-x-6)-x=log_{0}(n+8)-4(2) is No Solution for x\in\mathbb{R}