What is the answer to log_{x}(20)+log_{x}(5)=2 ?

The answer to log_{x}(20)+log_{x}(5)=2 is x=10

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log_{x}(20)+log_{x}(5)=2

lo g_{x} (20) + lo g_{x} (5) = 2

x = 10

Solution steps

lo g_{x} (20) + lo g_{x} (5) = 2

Apply log rules

\frac{ln ( 20 \cdot 5 )}{ln ( x )} = 2

Multiply both sides by

ln (x)

\frac{ln ( 20 \cdot 5 )}{ln ( x )} ln (x) = 2 ln (x)

Apply log rules

x = 10

Verify Solutions:

x = 10

True

The solution is

x = 10

lo g_{3} (lo g_{2} (x + 9)) = 1

ln (x^{2}) = 2 ln (x)

lo g_{16} (x) = \frac{3}{4}

b, ln (12 b) = 2 ln (b + 3 a) - ln (a)

\frac{lo g _{10} ( 80 )}{lo g _{10} ( 2 x )} = \frac{lo g _{10} ( 500 )}{lo g _{10} ( 5 x )}

What is the answer to log_{x}(20)+log_{x}(5)=2 ?
The answer to log_{x}(20)+log_{x}(5)=2 is x=10
Solve for x: log_{x}(20)+log_{x}(5)=2
The solution is x=10