What is the answer to log_{10}(x+5)+log_{10}(x-4)=log_{10}(10) ?

The answer to log_{10}(x+5)+log_{10}(x-4)=log_{10}(10) is x=5

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log_{10}(x+5)+log_{10}(x-4)=log_{10}(10)

lo g_{10} (x + 5) + lo g_{10} (x - 4) = lo g_{10} (10)

x = 5

Solution steps

lo g_{10} (x + 5) + lo g_{10} (x - 4) = lo g_{10} (10)

Apply log rules

(x + 5) (x - 4) = 10

Solve

(x + 5) (x - 4) = 10 : x = 5, x = - 6

x = 5, x = - 6

Verify Solutions:

x = 5

True

, x = - 6

False

The solution is

x = 5

lo g_{2} (4 x + 5) = lo g_{2} (9 - 2 x)

ln (x - 2) = x + 1

lo g_{10} (8 x) = \frac{11}{16}

lo g_{2} (x - l) = 2 \cdot lo g_{2} (x - 3)

lo g_{3} (x - 4) = 2

What is the answer to log_{10}(x+5)+log_{10}(x-4)=log_{10}(10) ?
The answer to log_{10}(x+5)+log_{10}(x-4)=log_{10}(10) is x=5
Solve for x: log_{10}(x+5)+log_{10}(x-4)=log_{10}(10)
The solution is x=5