What is 4x-3y+4=0,4x+3y-20=0 ?

The solution to 4x-3y+4=0,4x+3y-20=0 is x=2,y=4

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4x-3y+4=0,4x+3y-20=0

4 x - 3 y + 4 = 0, 4 x + 3 y - 20 = 0

x = 2, y = 4

Solution steps

[4 x - 3 y + 4 = 0 4 x + 3 y - 20 = 0]

Isolate

x

for

4 x - 3 y + 4 = 0 : x = \frac{3 y - 4}{4}

Substitute

x = \frac{3 y - 4}{4}

[4 \cdot \frac{3 y - 4}{4} + 3 y - 20 = 0]

Simplify

[6 y - 24 = 0]

Isolate

y

for

6 y - 24 = 0 : y = 4

For

x = \frac{3 y - 4}{4}

Substitute

y = 4

x = \frac{3 \cdot 4 - 4}{4}

\frac{3 \cdot 4 - 4}{4} = 2

x = 2

The solutions to the system of equations are:

x = 2, y = 4

5 x - 3 y = 20, 9 y - 4 x = 17

2 x + 3 y = 8, x - 2 y + 3 = 0

5 x + 7 y = 50, 9 x + 14 y = 97

122 x - 3 y + 7 = 0, 5 x + 2 y + 8 = 0

x + y = 2, 8 x - 3 y = 8