What are the solutions to the equation -u^2+32=0 ?

The solutions to the equation -u^2+32=0 are u=4sqrt(2),u=-4sqrt(2)

Find the zeros of -u^2+32=0

The zeros of -u^2+32=0 are u=4sqrt(2),u=-4sqrt(2)

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- u^{2} + 32 = 0

u = 42, u = - 42

Solution steps

- u^{2} + 32 = 0

Move

32

to the right side

- u^{2} = - 32

Divide both sides by

- 1

u^{2} = 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

u = 32, u = - 32

32 = 42

- 32 = - 42

u = 42, u = - 42

- \frac{14}{4}

x^{2} - x - 100 = - x

(- 13)^{2}

\frac{( a - b ) ^{2}}{a ^{2} - b ^{2}}

6^{2} + x^{2} = 1 2^{2}

What are the solutions to the equation -u^2+32=0 ?
The solutions to the equation -u^2+32=0 are u=4sqrt(2),u=-4sqrt(2)
Find the zeros of -u^2+32=0
The zeros of -u^2+32=0 are u=4sqrt(2),u=-4sqrt(2)