What are the solutions to the equation x^2-18x=-80 ?

The solutions to the equation x^2-18x=-80 are x=10,x=8

Find the zeros of x^2-18x=-80

The zeros of x^2-18x=-80 are x=10,x=8

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x^{2} - 18 x = - 80

x = 10, x = 8

Solution steps

x^{2} - 18 x = - 80

Move

80

to the left side

x^{2} - 18 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 80}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 80 = 2

x_{1, 2} = \frac{- ( - 18 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2}{2 \cdot 1} : 10

x = \frac{- ( - 18 ) - 2}{2 \cdot 1} : 8

The solutions to the quadratic equation are:

x = 10, x = 8

\frac{40 n ^{2} + 64 n}{16 n ^{3} + 112 n ^{2} + 160 n}

- 2 < x < 2

- 12 x^{2} + 12 x = 0

36 x^{2} + 16 x + 2 = 0

- \frac{4}{- 4}

What are the solutions to the equation x^2-18x=-80 ?
The solutions to the equation x^2-18x=-80 are x=10,x=8
Find the zeros of x^2-18x=-80
The zeros of x^2-18x=-80 are x=10,x=8