What is y^2=2x,y=x-4 ?

The solution to y^2=2x,y=x-4 is

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y^2=2x,y=x-4

y^{2} = 2 x, y = x - 4

(x = 8, x = 2, y = 4 y = - 2)

Solution steps

[y^{2} = 2 x y = x - 4]

Isolate

y

for

y = x - 4 : y = x - 4

Plug the solutions

y = x - 4

into

y^{2} = 2 x

For

y^{2} = 2 x

, subsitute

y

with

x - 4 : x = 8, x = 2

Plug the solutions

x = 8, x = 2

into

y = x - 4

For

y = x - 4

, subsitute

x

with

8 : y = 4

For

y = x - 4

, subsitute

x

with

2 : y = - 2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

y^{2} = 2 x, y = x - 4

are

(x = 8, x = 2, y = 4 y = - 2)

x y = - 4, 3 x + 4 y = - 22

x^{2} + y^{2} + 6 x + 2 y = 0, x + y = - 8

y^{2} = x + 1, y = x - 1

6 x + 3 y = 6, x y^{2} x + 4 y = 5 x y

g (x) = 2, x^{2} + x - 1 x = - \frac{1}{2}