What is y^2=x+1,y=x-1 ?

The solution to y^2=x+1,y=x-1 is

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y^2=x+1,y=x-1

y^{2} = x + 1, y = x - 1

(x = 3, x = 0, y = 2 y = - 1)

Solution steps

[y^{2} = x + 1 y = x - 1]

Subtract the equations

y^{2} = x + 1

y^{2} - y = x + 1 - (x - 1)

Simplify

y^{2} - y = 2

Solve

y^{2} - y = 2 : y = 2, y = - 1

Plug the solutions

y = 2, y = - 1

into

y^{2} = x + 1

For

y^{2} = x + 1

, subsitute

y

with

2 : x = 3

For

y^{2} = x + 1

, subsitute

y

with

- 1 : x = 0

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

y^{2} = x + 1, y = x - 1

are

(x = 3, x = 0, y = 2 y = - 1)

6 x + 3 y = 6, x y^{2} x + 4 y = 5 x y

g (x) = 2, x^{2} + x - 1 x = - \frac{1}{2}

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 7

y^{2} = 4 - x, y^{2} = 4 - 4 x

2 x + y + 2 z = 1, 3 x - y - 2 z = 6