What is g(x)=2,x^2+x-1x=-1/2 ?

The solution to g(x)=2,x^2+x-1x=-1/2 is

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g(x)=2,x^2+x-1x=-1/2

g (x) = 2, x^{2} + x - 1 x = - \frac{1}{2}

(x = i \frac{2}{2}, x = - i \frac{2}{2}, g = 2 g = 2)

Solution steps

[g = 2 x^{2} + x - 1 \cdot x = - \frac{1}{2}]

Solve

x^{2} + x - 1 x = - \frac{1}{2} : x = i \frac{2}{2}, x = - i \frac{2}{2}

Plug the solutions

x = i \frac{2}{2}, x = - i \frac{2}{2}

into

g = 2

For

g = 2

, subsitute

x

with

i \frac{2}{2} : g = 2

For

g = 2

, subsitute

x

with

- i \frac{2}{2} : g = 2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

g = 2, x^{2} + x - 1 x = - \frac{1}{2}

are

(x = i \frac{2}{2}, x = - i \frac{2}{2}, g = 2 g = 2)

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 7

y^{2} = 4 - x, y^{2} = 4 - 4 x

2 x + y + 2 z = 1, 3 x - y - 2 z = 6

x + y - z = 4, y - z = 1

+ \frac{x}{8} x = 2 y, y = 3