What is y^2=4-x,y^2=4-4x ?

The solution to y^2=4-x,y^2=4-4x is

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y^2=4-x,y^2=4-4x

y^{2} = 4 - x, y^{2} = 4 - 4 x

(x = 0, x = 0, y = 2 y = - 2)

Solution steps

[y^{2} = 4 - x y^{2} = 4 - 4 x]

Subtract the equations

y^{2} = 4 - x

y^{2} - y^{2} = 4 - x - (4 - 4 x)

Simplify

0 = 3 x

Solve

0 = 3 x : x = 0

Plug the solutions

x = 0

into

y^{2} = 4 - x

For

y^{2} = 4 - x

, subsitute

x

with

0 : y = 2, y = - 2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

y^{2} = 4 - x, y^{2} = 4 - 4 x

are

(x = 0, x = 0, y = 2 y = - 2)

2 x + y + 2 z = 1, 3 x - y - 2 z = 6

x + y - z = 4, y - z = 1

+ \frac{x}{8} x = 2 y, y = 3

\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0, a^{2} \frac{b}{x} + b^{2} \frac{a}{y} = a + b

f (x) = 6, x^{2} - 5 y^{2} + y = 6