What is f(x)=x^2-2x+3,f(x)=-2x+7 ?

The solution to f(x)=x^2-2x+3,f(x)=-2x+7 is

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f(x)=x^2-2x+3,f(x)=-2x+7

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 7

(x = 2, x = - 2, f = 3 f = 11)

Solution steps

[f = x^{2} - 2 x + 3 f = - 2 x + 7]

Subtract the equations

f = x^{2} - 2 x + 3

f - f = x^{2} - 2 x + 3 - (- 2 x + 7)

Simplify

0 = x^{2} - 4

Solve

0 = x^{2} - 4 : x = 2, x = - 2

Plug the solutions

x = 2, x = - 2

into

f = x^{2} - 2 x + 3

For

f = x^{2} - 2 x + 3

, subsitute

x

with

2 : f = 3

For

f = x^{2} - 2 x + 3

, subsitute

x

with

- 2 : f = 11

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

f = x^{2} - 2 x + 3, f = - 2 x + 7

are

(x = 2, x = - 2, f = 3 f = 11)

y^{2} = 4 - x, y^{2} = 4 - 4 x

2 x + y + 2 z = 1, 3 x - y - 2 z = 6

x + y - z = 4, y - z = 1

+ \frac{x}{8} x = 2 y, y = 3

\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0, a^{2} \frac{b}{x} + b^{2} \frac{a}{y} = a + b