What is (a^2)/x-(b^2)/y =0,a^2 b/x+b^2 a/y =a+b ?

The solution to (a^2)/x-(b^2)/y =0,a^2 b/x+b^2 a/y =a+b is

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(a^2)/x-(b^2)/y =0,a^2 b/x+b^2 a/y =a+b

\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0, a^{2} \frac{b}{x} + b^{2} \frac{a}{y} = a + b

(x = a^{2}, y = b^{2})

Solution steps

[\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0 a^{2} \frac{b}{x} + b^{2} \frac{a}{y} = a + b]

Isolate

x

for

\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0 : x = \frac{a ^{2} y}{b ^{2}}; b \neq = 0

Plug the solutions

x = \frac{a ^{2} y}{b ^{2}}

into

a^{2} \frac{b}{x} + b^{2} \frac{a}{y} = a + b

For

a^{2} \frac{b}{x} + b^{2} \frac{a}{y} = a + b

, subsitute

x

with

\frac{a ^{2} y}{b ^{2}} : y = b^{2}; a \neq = - b

Plug the solutions

y = b^{2}

into

\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0

For

\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0

, subsitute

y

with

b^{2} : x = a^{2}; b \neq = 0

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{a ^{2}}{x} - \frac{b ^{2}}{y} = 0, a^{2} \frac{b}{x} + b^{2} \frac{a}{y} = a + b

(x = a^{2}, y = b^{2})

f (x) = 6, x^{2} - 5 y^{2} + y = 6

4 x + 6 y = 3, x y^{8} x + 9 y = 5 x y

y^{2} = 2 x, x - y = 4

3 x - (9 x - y) = 5, y - (2 x + 9 y) 4 x - (3 y + 7) = 5 y - 47

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 28

What is (a^2)/x-(b^2)/y =0,a^2 b/x+b^2 a/y =a+b ?
The solution to (a^2)/x-(b^2)/y =0,a^2 b/x+b^2 a/y =a+b is