What is f(x)=6,x^2-5y^2+y=6 ?

The solution to f(x)=6,x^2-5y^2+y=6 is

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f(x)=6,x^2-5y^2+y=6

f (x) = 6, x^{2} - 5 y^{2} + y = 6

(x = 6 + 5 y^{2} - y, x = - 6 + 5 y^{2} - y, y \in R, y \in R, f = 6 f = 6)

Solution steps

[f = 6 x^{2} - 5 y^{2} + y = 6]

Solve

x^{2} - 5 y^{2} + y = 6

for

f = 6 : (x = 6 + 5 y^{2} - y, y \in R, f = 6), (x = - 6 + 5 y^{2} - y, y \in R, f = 6)

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

f = 6, x^{2} - 5 y^{2} + y = 6

are

(x = 6 + 5 y^{2} - y, x = - 6 + 5 y^{2} - y, y \in R, y \in R, f = 6 f = 6)

4 x + 6 y = 3, x y^{8} x + 9 y = 5 x y

y^{2} = 2 x, x - y = 4

3 x - (9 x - y) = 5, y - (2 x + 9 y) 4 x - (3 y + 7) = 5 y - 47

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 28

\frac{x}{y} - \frac{y}{x} = \frac{5}{6}, x^{2} - y^{2} = 5