What is y^2=2x,x-y=4 ?

The solution to y^2=2x,x-y=4 is

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y^2=2x,x-y=4

y^{2} = 2 x, x - y = 4

(x = 8, x = 2, y = 4 y = - 2)

Solution steps

[y^{2} = 2 x x - y = 4]

Isolate

x

for

x - y = 4 : x = 4 + y

Plug the solutions

x = 4 + y

into

y^{2} = 2 x

For

y^{2} = 2 x

, subsitute

x

with

4 + y : y = 4, y = - 2

Plug the solutions

y = 4, y = - 2

into

x - y = 4

For

x - y = 4

, subsitute

y

with

4 : x = 8

For

x - y = 4

, subsitute

y

with

- 2 : x = 2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

y^{2} = 2 x, x - y = 4

are

(x = 8, x = 2, y = 4 y = - 2)

3 x - (9 x - y) = 5, y - (2 x + 9 y) 4 x - (3 y + 7) = 5 y - 47

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 28

\frac{x}{y} - \frac{y}{x} = \frac{5}{6}, x^{2} - y^{2} = 5

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 19

\frac{( x + y )}{( x - y )} + \frac{( x - y )}{( x + y )} = \frac{13}{6}, x y = 5