What is f(x)=x^2-2x+3,f(x)=-2x+28 ?

The solution to f(x)=x^2-2x+3,f(x)=-2x+28 is

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f(x)=x^2-2x+3,f(x)=-2x+28

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 28

(x = 5, x = - 5, f = 18 f = 38)

Solution steps

[f = x^{2} - 2 x + 3 f = - 2 x + 28]

Subtract the equations

f = x^{2} - 2 x + 3

f - f = x^{2} - 2 x + 3 - (- 2 x + 28)

Simplify

0 = x^{2} - 25

Solve

0 = x^{2} - 25 : x = 5, x = - 5

Plug the solutions

x = 5, x = - 5

into

f = x^{2} - 2 x + 3

For

f = x^{2} - 2 x + 3

, subsitute

x

with

5 : f = 18

For

f = x^{2} - 2 x + 3

, subsitute

x

with

- 5 : f = 38

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

f = x^{2} - 2 x + 3, f = - 2 x + 28

are

(x = 5, x = - 5, f = 18 f = 38)

\frac{x}{y} - \frac{y}{x} = \frac{5}{6}, x^{2} - y^{2} = 5

f (x) = x^{2} - 2 x + 3, f (x) = - 2 x + 19

\frac{( x + y )}{( x - y )} + \frac{( x - y )}{( x + y )} = \frac{13}{6}, x y = 5

x^{2} + y^{2} = 2, 5 y x + y - 1 = 0

x + y = 2, x (x - y) = 12

What is f(x)=x^2-2x+3,f(x)=-2x+28 ?
The solution to f(x)=x^2-2x+3,f(x)=-2x+28 is