What is f(x)=x^2-5x+3,f(x)=-3 ?

The solution to f(x)=x^2-5x+3,f(x)=-3 is

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f(x)=x^2-5x+3,f(x)=-3

f (x) = x^{2} - 5 x + 3, f (x) = - 3

(x = 3, x = 2, f = - 3 f = - 3)

Solution steps

[f = x^{2} - 5 x + 3 f = - 3]

Plug the solutions

f = - 3

into

f = x^{2} - 5 x + 3

For

f = x^{2} - 5 x + 3

, subsitute

f

with

- 3 : x = 3, x = 2

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

f = x^{2} - 5 x + 3, f = - 3

are

(x = 3, x = 2, f = - 3 f = - 3)

y = - x^{2} + 2, y = x

2 x - 5 y = - 3, 2 x - 5 y = 3

x - y = 9, x \cdot y = 14

3 y + 43 = - 2, 5 x^{8} y - 12 x = 32

\frac{( a + 1 )}{5} = 1, \frac{6}{( b + 2 )} = c