What is x+y=1,y-15=-x^2+4x ?

The solution to x+y=1,y-15=-x^2+4x is

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x+y=1,y-15=-x^2+4x

x + y = 1, y - 15 = - x^{2} + 4 x

(x = 7, x = - 2, y = - 6 y = 3)

Solution steps

[x + y = 1 y - 15 = - x^{2} + 4 x]

Subtract the equations

x + y = 1

x + y - (y - 15) = 1 - (- x^{2} + 4 x)

Simplify

x + 15 = 1 + x^{2} - 4 x

Solve

x + 15 = 1 + x^{2} - 4 x : x = 7, x = - 2

Plug the solutions

x = 7, x = - 2

into

x + y = 1

For

x + y = 1

, subsitute

x

with

7 : y = - 6

For

x + y = 1

, subsitute

x

with

- 2 : y = 3

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x + y = 1, y - 15 = - x^{2} + 4 x

are

(x = 7, x = - 2, y = - 6 y = 3)

y^{2} = 9 x, x - y + 2 = 0

7 x + 2 y + 5 = 0, - 7 x - 2 y + 70 = 0

0.8 \frac{m}{s ^{2}} s = 2.5 u, a = 9

x^{2} - x - 3 x + 3 = 0, y^{2} - 3 y + 2 = 0

t^{2} y = 4 t, x = 2