What is 3a+2=3,b+4=3c+5 ?

The solution to 3a+2=3,b+4=3c+5 is a= 1/3 ,b=3c+1

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3a+2=3,b+4=3c+5

3 a + 2 = 3, b + 4 = 3 c + 5

a = \frac{1}{3}, b = 3 c + 1

Solution steps

[3 a + 2 = 3 b + 4 = 3 c + 5]

Isolate

a

for

3 a + 2 = 3 : a = \frac{1}{3}

[b + 4 = 3 c + 5]

Isolate

b

for

b + 4 = 3 c + 5 : b = 3 c + 1

The solutions to the system of equations are:

a = \frac{1}{3}, b = 3 c + 1

\frac{1}{x} + \frac{4}{y} = \frac{2}{7}, \frac{4}{3} x + \frac{1}{2} y = - \frac{8}{5}

f (x) (x)^{1} (x) = 1, + x f (x) (x)^{2} (x) = x^{2}

x + 3 y = 13, x^{2} + 3 y^{2} = 43

u (y, x) - 9 u (y, x) = (\frac{1}{2}) x^{4}, y = 6

0 + \frac{1}{2} yy = x + 150, x = 15