What is 5x^2-27x^2+36=0,y^2y+2=0 ?

The solution to 5x^2-27x^2+36=0,y^2y+2=0 is

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5x^2-27x^2+36=0,y^2y+2=0

5 x^{2} - 27 x^{2} + 36 = 0, y^{2} y + 2 = 0

Solution steps

[5 x^{2} - 27 x^{2} + 36 = 0 y^{2} y + 2 = 0]

Solve

5 x^{2} - 27 x^{2} + 36 = 0 : x = - \frac{3 2}{11}, x = \frac{3 2}{11}

For

y^{2} y + 2 = 0

, subsitute

x

with

For

y^{2} y + 2 = 0

, subsitute

x

with

Solve

For

5 x^{2} - 27 x^{2} + 36 = 0

, subsitute

y

with

For

5 x^{2} - 27 x^{2} + 36 = 0

, subsitute

y

with

For

5 x^{2} - 27 x^{2} + 36 = 0

, subsitute

y

with

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

5 x^{2} - 27 x^{2} + 36 = 0, y^{2} y + 2 = 0

are

f (x) = 2, x^{2} + 8 x - 3 x^{0} = - 3

2 x^{3} y = 1, 0.93 x y = 1.1

8 x^{4} - 3 y = 17, 7 x - 4 y = 8

x - y = - 6, x^{2} - y = - 4

6 x^{2} + 7 x - 3 = 0, x_{1} = x_{2}