What are the solutions to the equation 5x^2-31x+6=0 ?

The solutions to the equation 5x^2-31x+6=0 are x=6,x= 1/5

Find the zeros of 5x^2-31x+6=0

The zeros of 5x^2-31x+6=0 are x=6,x= 1/5

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5 x^{2} - 31 x + 6 = 0

x = 6, x = \frac{1}{5}

Decimal Notation

x = 6, x = 0.2

Solution steps

5 x^{2} - 31 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 31 ) \pm ( - 31 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

(- 31)^{2} - 4 \cdot 5 \cdot 6 = 29

x_{1, 2} = \frac{- ( - 31 ) \pm 29}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 31 ) + 29}{2 \cdot 5}, x_{2} = \frac{- ( - 31 ) - 29}{2 \cdot 5}

x = \frac{- ( - 31 ) + 29}{2 \cdot 5} : 6

x = \frac{- ( - 31 ) - 29}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 6, x = \frac{1}{5}

(4)^{3}

0.0001 = 2.5263 \cdot 1 0^{- 9} (x - (6 \cdot 1 0^{3}))

3 (2 x + 1) - \frac{x + 1}{2} = \frac{1}{2} [x + 2 - \frac{x + 1}{3}]

∣ 1 - 7 x ∣ + 5 \geq 8

y^{2} - 10 y = - 14

What are the solutions to the equation 5x^2-31x+6=0 ?
The solutions to the equation 5x^2-31x+6=0 are x=6,x= 1/5
Find the zeros of 5x^2-31x+6=0
The zeros of 5x^2-31x+6=0 are x=6,x= 1/5