What is factor (m^{16}+9m^8+8)/(4m^{10)+32m^2} ?

The solution to factor (m^{16}+9m^8+8)/(4m^{10)+32m^2} is (m^8+1)/(4m^2)

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factor (m^{16}+9m^8+8)/(4m^{10)+32m^2}

factor

\frac{m ^{16} + 9 m ^{8} + 8}{4 m ^{10} + 32 m ^{2}}

\frac{m ^{8} + 1}{4 m ^{2}}

Solution steps

\frac{m ^{16} + 9 m ^{8} + 8}{4 m ^{10} + 32 m ^{2}}

Factor

m^{16} + 9 m^{8} + 8 : (m^{8} + 1) (m^{8} + 8)

= \frac{( m ^{8} + 1 ) ( m ^{8} + 8 )}{4 m ^{10} + 32 m ^{2}}

Factor out common term

4 m^{2} : 4 m^{2} (m^{8} + 8)

= \frac{( m ^{8} + 1 ) ( m ^{8} + 8 )}{4 m ^{2} ( m ^{8} + 8 )}

Cancel the common factor:

m^{8} + 8

= \frac{m ^{8} + 1}{4 m ^{2}}

\frac{- x}{3} + \frac{2}{3} + 3 \leq x

4 x^{2} + x + 2 = 0

(x + 1) (x - 2) (x - 3) \leq 0

4 x^{2} + 20 x = - 21

4 x^{2} + x = 0

What is factor (m^{16}+9m^8+8)/(4m^{10)+32m^2} ?
The solution to factor (m^{16}+9m^8+8)/(4m^{10)+32m^2} is (m^8+1)/(4m^2)