What are the solutions to the equation 4x^2+20x=-21 ?

The solutions to the equation 4x^2+20x=-21 are x=-3/2 ,x=-7/2

Find the zeros of 4x^2+20x=-21

The zeros of 4x^2+20x=-21 are x=-3/2 ,x=-7/2

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4 x^{2} + 20 x = - 21

x = - \frac{3}{2}, x = - \frac{7}{2}

Decimal Notation

x = - 1.5, x = - 3.5

Solution steps

4 x^{2} + 20 x = - 21

Move

21

to the left side

4 x^{2} + 20 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 21 = 8

x_{1, 2} = \frac{- 20 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 8}{2 \cdot 4}, x_{2} = \frac{- 20 - 8}{2 \cdot 4}

x = \frac{- 20 + 8}{2 \cdot 4} : - \frac{3}{2}

x = \frac{- 20 - 8}{2 \cdot 4} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - \frac{7}{2}

4 x^{2} + x = 0

- 8 < - 2 z + 4 < 10

- \frac{3}{4} (x + 2) = 6

x^{2} - x - 9 = 0

- \frac{0.9 ( 10 )}{( 0.01 ( 10 ) ^{2} + 1 ) ^{2}}

What are the solutions to the equation 4x^2+20x=-21 ?
The solutions to the equation 4x^2+20x=-21 are x=-3/2 ,x=-7/2
Find the zeros of 4x^2+20x=-21
The zeros of 4x^2+20x=-21 are x=-3/2 ,x=-7/2