What is sqrt(2/((3x-5)))>= 0 ?

The solution to sqrt(2/((3x-5)))>= 0 is x> 5/3

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sqrt(2/((3x-5)))>= 0

\frac{2}{( 3 x - 5 )} \geq 0

x > \frac{5}{3}

Interval Notation

(\frac{5}{3}, \infty)

Decimal Notation

x > 1.66666 \dots

Solution steps

\frac{2}{3 x - 5} \geq 0

If n is even,

for all

u

True for all x

Find singularity points

Find non-negative values for radicals:

x > \frac{5}{3}

Combine the intervals

True for all x and x > \frac{5}{3}

Merge Overlapping Intervals

x > \frac{5}{3}

3 - x > 3 (1 - x^{2})^{\frac{1}{2}}

x + 5 - 25 - 10 x + x^{2} \leq 2 x

2 x \leq x^{2}

x - 4 < - 3

x^{2} - 4 x + 3 \geq 2 - x