What is longdivision ((x^3-3x^2+5x-2))/(x+5) ?

The solution to longdivision ((x^3-3x^2+5x-2))/(x+5) is x^2-8x+45-(227)/(x+5)

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longdivision ((x^3-3x^2+5x-2))/(x+5)

long division

\frac{( x ^{3} - 3 x ^{2} + 5 x - 2 )}{x + 5}

x^{2} - 8 x + 45 - \frac{227}{x + 5}

Solution steps

\frac{( x ^{3} - 3 x ^{2} + 5 x - 2 )}{x + 5}

Divide

\frac{x ^{3} - 3 x ^{2} + 5 x - 2}{x + 5} : \frac{x ^{3} - 3 x ^{2} + 5 x - 2}{x + 5} = x^{2} + \frac{- 8 x ^{2} + 5 x - 2}{x + 5}

= x^{2} + \frac{- 8 x ^{2} + 5 x - 2}{x + 5}

Divide

\frac{- 8 x ^{2} + 5 x - 2}{x + 5} : \frac{- 8 x ^{2} + 5 x - 2}{x + 5} = - 8 x + \frac{45 x - 2}{x + 5}

= x^{2} - 8 x + \frac{45 x - 2}{x + 5}

Divide

\frac{45 x - 2}{x + 5} : \frac{45 x - 2}{x + 5} = 45 + \frac{- 227}{x + 5}

= x^{2} - 8 x + 45 + \frac{- 227}{x + 5}

Simplify

= x^{2} - 8 x + 45 - \frac{227}{x + 5}

\frac{6 x ^{3} + 3 x ^{2} - 5}{3 x ^{2} + 1}

\frac{x ^{2} + 4 x - 1}{x + 2}

\frac{( x ^{2} - 1 )}{( x - 9 )}

\frac{( 243 x ^{5} - 1 )}{( 3 x + 1 )}

\frac{( x ^{2} + 1 )}{( x + 1 )}

What is longdivision ((x^3-3x^2+5x-2))/(x+5) ?
The solution to longdivision ((x^3-3x^2+5x-2))/(x+5) is x^2-8x+45-(227)/(x+5)