What are the solutions to the equation (x-2)(3x+4)=0 ?

The solutions to the equation (x-2)(3x+4)=0 are x=2,x=-4/3

Find the zeros of (x-2)(3x+4)=0

The zeros of (x-2)(3x+4)=0 are x=2,x=-4/3

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(x - 2) (3 x + 4) = 0

x = 2, x = - \frac{4}{3}

Solution steps

(x - 2) (3 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 3 x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = 2, x = - \frac{4}{3}

z^{2} + 5 z - 14 = 0

7 b - 52 = 6 b - 57

x^{2} + 10 x + 12 = 2 x + 5

- 3 \cdot - 15

9 w - 4 \geq 7 + 11 w

What are the solutions to the equation (x-2)(3x+4)=0 ?
The solutions to the equation (x-2)(3x+4)=0 are x=2,x=-4/3
Find the zeros of (x-2)(3x+4)=0
The zeros of (x-2)(3x+4)=0 are x=2,x=-4/3