What is factor x^4-4x^3-x^2+16x-12 ?

The solution to factor x^4-4x^3-x^2+16x-12 is (x-1)(x-3)(x+2)(x-2)

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factor x^4-4x^3-x^2+16x-12

factor

x^{4} - 4 x^{3} - x^{2} + 16 x - 12

(x - 1) (x - 3) (x + 2) (x - 2)

Solution steps

x^{4} - 4 x^{3} - x^{2} + 16 x - 12

Use the rational root theorem

= (x - 1) \frac{x ^{4} - 4 x ^{3} - x ^{2} + 16 x - 12}{x - 1}

\frac{x ^{4} - 4 x ^{3} - x ^{2} + 16 x - 12}{x - 1} = x^{3} - 3 x^{2} - 4 x + 12

= (x - 1) (x^{3} - 3 x^{2} - 4 x + 12)

Factor

x^{3} - 3 x^{2} - 4 x + 12 : (x - 3) (x + 2) (x - 2)

= (x - 1) (x - 3) (x + 2) (x - 2)

(2 w^{4} v^{- 5})^{- 2}

2^{2} + 4^{2} + 6^{2}

(2 x + y^{2})^{2}

(6 x + 7) + (8 x^{2} + 5 x - 1)

- 27 \div 3

What is factor x^4-4x^3-x^2+16x-12 ?
The solution to factor x^4-4x^3-x^2+16x-12 is (x-1)(x-3)(x+2)(x-2)