What are the solutions to the equation 2p^2+8p=-7 ?

The solutions to the equation 2p^2+8p=-7 are p=(-4+sqrt(2))/2 ,p=-(4+sqrt(2))/2

Find the zeros of 2p^2+8p=-7

The zeros of 2p^2+8p=-7 are p=(-4+sqrt(2))/2 ,p=-(4+sqrt(2))/2

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2 p^{2} + 8 p = - 7

p = \frac{- 4 + 2}{2}, p = - \frac{4 + 2}{2}

Solution steps

2 p^{2} + 8 p = - 7

Move

7

to the left side

2 p^{2} + 8 p + 7 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 7 = 22

p_{1, 2} = \frac{- 8 \pm 2 2}{2 \cdot 2}

Separate the solutions

p_{1} = \frac{- 8 + 2 2}{2 \cdot 2}, p_{2} = \frac{- 8 - 2 2}{2 \cdot 2}

p = \frac{- 8 + 2 2}{2 \cdot 2} : \frac{- 4 + 2}{2}

p = \frac{- 8 - 2 2}{2 \cdot 2} : - \frac{4 + 2}{2}

The solutions to the quadratic equation are:

p = \frac{- 4 + 2}{2}, p = - \frac{4 + 2}{2}

\frac{2 π}{\frac{3}{2}}

∣ a - 1 ∣ + 4 ∣ a - 3 ∣ = 2 ∣ a + 2 ∣

a x + b x + a y + b y

6 y^{2} - 5 y - 6 = 0

y^{3} - 8 z^{3}

What are the solutions to the equation 2p^2+8p=-7 ?
The solutions to the equation 2p^2+8p=-7 are p=(-4+sqrt(2))/2 ,p=-(4+sqrt(2))/2
Find the zeros of 2p^2+8p=-7
The zeros of 2p^2+8p=-7 are p=(-4+sqrt(2))/2 ,p=-(4+sqrt(2))/2