What are the solutions to the equation x^2+18x+71=0 ?

The solutions to the equation x^2+18x+71=0 are x=-9+sqrt(10),x=-9-sqrt(10)

Find the zeros of x^2+18x+71=0

The zeros of x^2+18x+71=0 are x=-9+sqrt(10),x=-9-sqrt(10)

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x^{2} + 18 x + 71 = 0

x = - 9 + 10, x = - 9 - 10

Solution steps

x^{2} + 18 x + 71 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 71}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 71 = 210

x_{1, 2} = \frac{- 18 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 10}{2 \cdot 1}

x = \frac{- 18 + 2 10}{2 \cdot 1} : - 9 + 10

x = \frac{- 18 - 2 10}{2 \cdot 1} : - 9 - 10

The solutions to the quadratic equation are:

x = - 9 + 10, x = - 9 - 10

∣ x + 3 ∣ \leq 4

3 x^{2} - 10 x - 7 = 0

\frac{( \frac{1}{4} )}{2}

∣ 4 x - 5 ∣ \leq 12

\frac{1}{2} x = 32

What are the solutions to the equation x^2+18x+71=0 ?
The solutions to the equation x^2+18x+71=0 are x=-9+sqrt(10),x=-9-sqrt(10)
Find the zeros of x^2+18x+71=0
The zeros of x^2+18x+71=0 are x=-9+sqrt(10),x=-9-sqrt(10)