What are the solutions to the equation 3b(9b-27)=0 ?

The solutions to the equation 3b(9b-27)=0 are b=0,b=3

Find the zeros of 3b(9b-27)=0

The zeros of 3b(9b-27)=0 are b=0,b=3

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3 b (9 b - 27) = 0

b = 0, b = 3

Solution steps

3 b (9 b - 27) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

b = 0 or 9 b - 27 = 0

Solve

9 b - 27 = 0 : b = 3

The solutions to the quadratic equation are:

b = 0, b = 3

x^{2} + 28 x + 83 = 9 x - 7

\frac{3 + i}{2 - i} + \frac{1}{1 + i}

7 x^{2} - 16 x = 8

x^{2} + 8 x + 12 = 0

6 x^{2} + x - 15

What are the solutions to the equation 3b(9b-27)=0 ?
The solutions to the equation 3b(9b-27)=0 are b=0,b=3
Find the zeros of 3b(9b-27)=0
The zeros of 3b(9b-27)=0 are b=0,b=3