What are the solutions to the equation 4x^2+5=4x ?

The solutions to the equation 4x^2+5=4x are x= 1/2+i,x= 1/2-i

Find the zeros of 4x^2+5=4x

The zeros of 4x^2+5=4x are x= 1/2+i,x= 1/2-i

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4 x^{2} + 5 = 4 x

x = \frac{1}{2} + i, x = \frac{1}{2} - i

Solution steps

4 x^{2} + 5 = 4 x

Move

4 x

to the left side

4 x^{2} + 5 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 5 : 8 i

x_{1, 2} = \frac{- ( - 4 ) \pm 8 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 8 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8 i}{2 \cdot 4} : \frac{1}{2} + i

x = \frac{- ( - 4 ) - 8 i}{2 \cdot 4} : \frac{1}{2} - i

The solutions to the quadratic equation are:

x = \frac{1}{2} + i, x = \frac{1}{2} - i

x^{2} - 8 x - 16 = 0

6 x^{2} + 6 x + 7 = 0

x^{3} \cdot x^{\frac{1}{2}}

1 - \frac{2}{x} > 3 x

\frac{2 + 3 i}{4 + i}

What are the solutions to the equation 4x^2+5=4x ?
The solutions to the equation 4x^2+5=4x are x= 1/2+i,x= 1/2-i
Find the zeros of 4x^2+5=4x
The zeros of 4x^2+5=4x are x= 1/2+i,x= 1/2-i