What are the solutions to the equation (5x+1)^2-2x(5x+1)=0 ?

The solutions to the equation (5x+1)^2-2x(5x+1)=0 are x=-1/5 ,x=-1/3

Find the zeros of (5x+1)^2-2x(5x+1)=0

The zeros of (5x+1)^2-2x(5x+1)=0 are x=-1/5 ,x=-1/3

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(5 x + 1)^{2} - 2 x (5 x + 1) = 0

x = - \frac{1}{5}, x = - \frac{1}{3}

Decimal Notation

x = - 0.2, x = - 0.33333 \dots

Solution steps

(5 x + 1)^{2} - 2 x (5 x + 1) = 0

Expand

(5 x + 1)^{2} - 2 x (5 x + 1) : 15 x^{2} + 8 x + 1

15 x^{2} + 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 15 \cdot 1}{2 \cdot 15}

8^{2} - 4 \cdot 15 \cdot 1 = 2

x_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 8 + 2}{2 \cdot 15}, x_{2} = \frac{- 8 - 2}{2 \cdot 15}

x = \frac{- 8 + 2}{2 \cdot 15} : - \frac{1}{5}

x = \frac{- 8 - 2}{2 \cdot 15} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - \frac{1}{3}

3 x^{2} - 8 = - 155

5 a^{2} - 31 a = 28

∣ x - 6 ∣ = 26

x^{2} - 4 x - 9 = 0

\frac{1}{3}

What are the solutions to the equation (5x+1)^2-2x(5x+1)=0 ?
The solutions to the equation (5x+1)^2-2x(5x+1)=0 are x=-1/5 ,x=-1/3
Find the zeros of (5x+1)^2-2x(5x+1)=0
The zeros of (5x+1)^2-2x(5x+1)=0 are x=-1/5 ,x=-1/3