What is 2x^3+3x^2-18x+8<= 0 ?

The solution to 2x^3+3x^2-18x+8<= 0 is x<=-4\lor 1/2 <= x<= 2

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2x^3+3x^2-18x+8<= 0

2 x^{3} + 3 x^{2} - 18 x + 8 \leq 0

x \leq - 4 or \frac{1}{2} \leq x \leq 2

Interval Notation

(- \infty, - 4] \cup [\frac{1}{2}, 2]

Decimal Notation

x \leq - 4 or 0.5 \leq x \leq 2

Solution steps

2 x^{3} + 3 x^{2} - 18 x + 8 \leq 0

Factor

2 x^{3} + 3 x^{2} - 18 x + 8 : (x - 2) (2 x - 1) (x + 4)

(x - 2) (2 x - 1) (x + 4) \leq 0

Identify the intervals

x \leq - 4 or \frac{1}{2} \leq x \leq 2

100 x^{3} + 25 x^{2} + 4 x + 1 = 0

\frac{n}{5} \leq 2

2 x^{2} + 7 = 4 x

\frac{2 q ^{- 9} b}{5 ( q ^{- 5} b ^{- 4} ) ^{2}}

(\frac{z}{5})^{2}

What is 2x^3+3x^2-18x+8<= 0 ?
The solution to 2x^3+3x^2-18x+8<= 0 is x<=-4\lor 1/2 <= x<= 2