What are the solutions to the equation s^2-14s+45=0 ?

The solutions to the equation s^2-14s+45=0 are s=9,s=5

Find the zeros of s^2-14s+45=0

The zeros of s^2-14s+45=0 are s=9,s=5

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s^{2} - 14 s + 45 = 0

s = 9, s = 5

Solution steps

s^{2} - 14 s + 45 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 45}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 45 = 4

s_{1, 2} = \frac{- ( - 14 ) \pm 4}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 14 ) + 4}{2 \cdot 1}, s_{2} = \frac{- ( - 14 ) - 4}{2 \cdot 1}

s = \frac{- ( - 14 ) + 4}{2 \cdot 1} : 9

s = \frac{- ( - 14 ) - 4}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

s = 9, s = 5

26 < x + 16

\frac{x ^{- 2}}{x ^{4}}

2 x^{2} + 9 x - 1 = 0

\frac{- 9 - 2 i}{- 8 - i}

e^{2 l n (7)}

What are the solutions to the equation s^2-14s+45=0 ?
The solutions to the equation s^2-14s+45=0 are s=9,s=5
Find the zeros of s^2-14s+45=0
The zeros of s^2-14s+45=0 are s=9,s=5