What are the solutions to the equation (2x-3)^2=25 ?

The solutions to the equation (2x-3)^2=25 are x=4,x=-1

Find the zeros of (2x-3)^2=25

The zeros of (2x-3)^2=25 are x=4,x=-1

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(2 x - 3)^{2} = 25

x = 4, x = - 1

Solution steps

(2 x - 3)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 3 = 25 : x = 4

Solve

2 x - 3 = - 25 : x = - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

x^{2} + 16 x + 7 = 0

\frac{- 2 - 6 i}{- 1 - 3 i}

27 x^{6} - 64 y^{6}

x - 5 = 1

1 (- 4.94 b - 19.24) = - 4 b - 28.64

What are the solutions to the equation (2x-3)^2=25 ?
The solutions to the equation (2x-3)^2=25 are x=4,x=-1
Find the zeros of (2x-3)^2=25
The zeros of (2x-3)^2=25 are x=4,x=-1