What are the solutions to the equation t^2-6t+4=5 ?

The solutions to the equation t^2-6t+4=5 are t=3+sqrt(10),t=3-sqrt(10)

Find the zeros of t^2-6t+4=5

The zeros of t^2-6t+4=5 are t=3+sqrt(10),t=3-sqrt(10)

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t^{2} - 6 t + 4 = 5

t = 3 + 10, t = 3 - 10

Solution steps

t^{2} - 6 t + 4 = 5

Move

5

to the left side

t^{2} - 6 t - 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 1) = 210

t_{1, 2} = \frac{- ( - 6 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 6 ) + 2 10}{2 \cdot 1}, t_{2} = \frac{- ( - 6 ) - 2 10}{2 \cdot 1}

t = \frac{- ( - 6 ) + 2 10}{2 \cdot 1} : 3 + 10

t = \frac{- ( - 6 ) - 2 10}{2 \cdot 1} : 3 - 10

The solutions to the quadratic equation are:

t = 3 + 10, t = 3 - 10

\frac{5}{x - 4} < \frac{1}{x + 4}

\frac{w + 3}{4} = \frac{w - 2}{2}

(8 x + 7) (x + 1) = 9

6 x^{2} - 17 x + 13 = 20 x^{2} - 32

∣ 1 - 4 x ∣ - 11 < - 8

What are the solutions to the equation t^2-6t+4=5 ?
The solutions to the equation t^2-6t+4=5 are t=3+sqrt(10),t=3-sqrt(10)
Find the zeros of t^2-6t+4=5
The zeros of t^2-6t+4=5 are t=3+sqrt(10),t=3-sqrt(10)