What are the solutions to the equation x^2+x=0 ?

The solutions to the equation x^2+x=0 are x=0,x=-1

Find the zeros of x^2+x=0

The zeros of x^2+x=0 are x=0,x=-1

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x^{2} + x = 0

x = 0, x = - 1

Solution steps

x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 1}, x_{2} = \frac{- 1 - 1}{2 \cdot 1}

x = \frac{- 1 + 1}{2 \cdot 1} : 0

x = \frac{- 1 - 1}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 0, x = - 1

2 \cdot 0.25

3 u^{2} + 5 u = - 2

4 ∣ x - 2 ∣ + 1 = 21

x^{2} + 10 x y + 25 y^{2}

\frac{∣ 3 x + 1 ∣}{∣ x + 3 ∣} < 1

What are the solutions to the equation x^2+x=0 ?
The solutions to the equation x^2+x=0 are x=0,x=-1
Find the zeros of x^2+x=0
The zeros of x^2+x=0 are x=0,x=-1