What is expand ((4x-1)(2x+3))/(18x-4) ?

The solution to expand ((4x-1)(2x+3))/(18x-4) is (8x^2+10x-3)/(18x-4)

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expand ((4x-1)(2x+3))/(18x-4)

expand

\frac{( 4 x - 1 ) ( 2 x + 3 )}{18 x - 4}

\frac{8 x ^{2} + 10 x - 3}{18 x - 4}

Solution steps

\frac{( 4 x - 1 ) ( 2 x + 3 )}{18 x - 4}

Expand

(4 x - 1) (2 x + 3) : 8 x^{2} + 10 x - 3

= \frac{8 x ^{2} + 10 x - 3}{18 x - 4}

e^{3 x} (e^{2 x} - e^{x})

(e^{2 x} - 4) (e^{2 x} + 4)

(e^{3 x} + 6) (e^{3 x} - 4)

(e^{2 x} - 4) (e^{- 2 x} - 4)

(x + Δ x)^{2} - 4 (x + Δ x)

What is expand ((4x-1)(2x+3))/(18x-4) ?
The solution to expand ((4x-1)(2x+3))/(18x-4) is (8x^2+10x-3)/(18x-4)