What is expand Z(2x-1)dx(x-1)(x-2)(x-3) ?

The solution to expand Z(2x-1)dx(x-1)(x-2)(x-3) is 2Zx^4dx-13Zx^3dx+28Zx^2dx-23Zxdx+6Zdx

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expand Z(2x-1)dx(x-1)(x-2)(x-3)

expand

Z (2 x - 1) d x (x - 1) (x - 2) (x - 3)

2 Z x^{4} d x - 13 Z x^{3} d x + 28 Z x^{2} d x - 23 Z x d x + 6 Z d x

Solution steps

Z (2 x - 1) d x (x - 1) (x - 2) (x - 3)

Expand

(2 x - 1) (x - 1) : 2 x^{2} - 3 x + 1

= Z d x (2 x^{2} - 3 x + 1) (x - 2) (x - 3)

Expand

(2 x^{2} - 3 x + 1) (x - 2) : 2 x^{3} - 7 x^{2} + 7 x - 2

= Z d x (2 x^{3} - 7 x^{2} + 7 x - 2) (x - 3)

Expand

(2 x^{3} - 7 x^{2} + 7 x - 2) (x - 3) : 2 x^{4} - 13 x^{3} + 28 x^{2} - 23 x + 6

= Z d x (2 x^{4} - 13 x^{3} + 28 x^{2} - 23 x + 6)

Expand

Z d x (2 x^{4} - 13 x^{3} + 28 x^{2} - 23 x + 6) : 2 Z x^{4} d x - 13 Z x^{3} d x + 28 Z x^{2} d x - 23 Z x d x + 6 Z d x

= 2 Z x^{4} d x - 13 Z x^{3} d x + 28 Z x^{2} d x - 23 Z x d x + 6 Z d x

\frac{( x ^{2} + 1 ) ( 2 x + 3 )}{3 x - 1}

(e^{t} + 2 e^{2 t})^{2}

(- 2, - 11) Y (4, 7)

\frac{2}{( 1 - x ) ( 1 + x ^{2} )}

(2 x^{2} + 3 x - 4) - (x^{2} + x = 8)

What is expand Z(2x-1)dx(x-1)(x-2)(x-3) ?
The solution to expand Z(2x-1)dx(x-1)(x-2)(x-3) is 2Zx^4dx-13Zx^3dx+28Zx^2dx-23Zxdx+6Zdx