What is expand ((x+3)(x+2)(x-5))/(2x+1) ?

The solution to expand ((x+3)(x+2)(x-5))/(2x+1) is (x^3-19x-30)/(2x+1)

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expand ((x+3)(x+2)(x-5))/(2x+1)

expand

\frac{( x + 3 ) ( x + 2 ) ( x - 5 )}{2 x + 1}

\frac{x ^{3} - 19 x - 30}{2 x + 1}

Solution steps

\frac{( x + 3 ) ( x + 2 ) ( x - 5 )}{2 x + 1}

Expand

(x + 3) (x + 2) (x - 5) : x^{3} - 19 x - 30

= \frac{x ^{3} - 19 x - 30}{2 x + 1}

9^{2} - 100

l (e^{x} + e^{- x}) sin (x)

(\frac{( k ( 3 k + 1 ) )}{2}) + (3 k + 1)

\frac{( - 4 + 5 x ) ^{2}}{16}

2 (- 3 x - 5 y = - 2)

What is expand ((x+3)(x+2)(x-5))/(2x+1) ?
The solution to expand ((x+3)(x+2)(x-5))/(2x+1) is (x^3-19x-30)/(2x+1)