What is expand 2-3(x^2+2Δx+Δx^2) ?

The solution to expand 2-3(x^2+2Δx+Δx^2) is 2-3x^2-6Δx-3Δx^2

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expand 2-3(x^2+2Δx+Δx^2)

expand

2 - 3 (x^{2} + 2Δ x + Δ x^{2})

2 - 3 x^{2} - 6Δ x - 3Δ x^{2}

Solution steps

2 - 3 (x^{2} + 2Δ x + Δ x^{2})

Expand

- 3 (x^{2} + 2Δ x + Δ x^{2}) : - 3 x^{2} - 6Δ x - 3Δ x^{2}

= 2 - 3 x^{2} - 6Δ x - 3Δ x^{2}

\frac{( 3244 - 283 x ) 3}{5}

(f \circ g) (x + 2) (2 x - 1)

\frac{1}{( 2 + sin ( θ ) ) ^{4}}

(1 - ln (x)) d x + (1 - ln (y)) d y

\frac{( 3 x ^{2} - x ) ^{3}}{3}

What is expand 2-3(x^2+2Δx+Δx^2) ?
The solution to expand 2-3(x^2+2Δx+Δx^2) is 2-3x^2-6Δx-3Δx^2