What is (e^{ix}-1)^2 ?

The solution to (e^{ix}-1)^2 is (cos(x)+isin(x)-1)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (e^{ix}-1)^2

simplify

(e^{i x} - 1)^{2}

(cos (x) + i sin (x) - 1)^{2}

Solution steps

(e^{i x} - 1)^{2}

Apply imaginary number rule:

e^{ia} = cos (a) + i sin (a)

= (cos (x) + i sin (x) - 1)^{2}

- 3 (2 h - 4 = 20 - 4 h)

\frac{( 3 x - 2 ) ( x + 1 )}{x + 2}

- x^{2} e^{- x} - 2 e^{- x} (x + 1) + 2

\frac{( ( n + 1 ) ( n + 2 ) ( 2 n + 3 ) )}{6}

2 h (x) - (6 x - 1 - 5 = - 1)