expand (2x+1)ln(3)

الحلّ

expand

(2 x + 1) ln (3)

2 ln (3) x + ln (3)

خطوات الحلّ

(2 x + 1) ln (3)

= ln (3) (2 x + 1)

a (b + c) = ab + a c

: افتح أقواس بالاستعانة بـ

a = ln (3), b = 2 x, c = 1

= ln (3) \cdot 2 x + ln (3) \cdot 1

= 2 ln (3) x + 1 \cdot ln (3)

1 \cdot ln (3) = ln (3) :

اضرب

= 2 ln (3) x + ln (3)

\frac{( 100 - 94 cos ( x ) ) ^{2}}{4}

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(\frac{( 3 y - 3 )}{2})^{2}