What is expand ((x-6)(x+1))/((x-3)(x+2)) ?

The solution to expand ((x-6)(x+1))/((x-3)(x+2)) is (x^2-5x-6)/(x^2-x-6)

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expand ((x-6)(x+1))/((x-3)(x+2))

expand

\frac{( x - 6 ) ( x + 1 )}{( x - 3 ) ( x + 2 )}

\frac{x ^{2} - 5 x - 6}{x ^{2} - x - 6}

Solution steps

\frac{( x - 6 ) ( x + 1 )}{( x - 3 ) ( x + 2 )}

Expand

(x - 3) (x + 2) : x^{2} - x - 6

= \frac{( x - 6 ) ( x + 1 )}{x ^{2} - x - 6}

Expand

(x - 6) (x + 1) : x^{2} - 5 x - 6

= \frac{x ^{2} - 5 x - 6}{x ^{2} - x - 6}

(x^{2} (1 + x))!

\frac{( 4 s ^{2} - 1 ) ^{2}}{s ^{6}}

- \frac{( x + 1 ) ( x - 4 )}{6}

\frac{( x + 4 ) ^{2}}{2}

\frac{4 ( 2 x + 5 y )}{13 x}

What is expand ((x-6)(x+1))/((x-3)(x+2)) ?
The solution to expand ((x-6)(x+1))/((x-3)(x+2)) is (x^2-5x-6)/(x^2-x-6)