What is expand ((4s^2-1)^2)/(s^6) ?

The solution to expand ((4s^2-1)^2)/(s^6) is (16)/(s^2)-8/(s^4)+1/(s^6)

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expand ((4s^2-1)^2)/(s^6)

expand

\frac{( 4 s ^{2} - 1 ) ^{2}}{s ^{6}}

\frac{16}{s ^{2}} - \frac{8}{s ^{4}} + \frac{1}{s ^{6}}

Solution steps

\frac{( 4 s ^{2} - 1 ) ^{2}}{s ^{6}}

(4 s^{2} - 1)^{2} = 16 s^{4} - 8 s^{2} + 1

= \frac{16 s ^{4} - 8 s ^{2} + 1}{s ^{6}}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 s ^{4} - 8 s ^{2} + 1}{s ^{6}} = \frac{16 s ^{4}}{s ^{6}} - \frac{8 s ^{2}}{s ^{6}} + \frac{1}{s ^{6}}

= \frac{16 s ^{4}}{s ^{6}} - \frac{8 s ^{2}}{s ^{6}} + \frac{1}{s ^{6}}

Cancel

\frac{16 s ^{4}}{s ^{6}} : \frac{16}{s ^{2}}

= \frac{16}{s ^{2}} - \frac{8 s ^{2}}{s ^{6}} + \frac{1}{s ^{6}}

Cancel

\frac{8 s ^{2}}{s ^{6}} : \frac{8}{s ^{4}}

= \frac{16}{s ^{2}} - \frac{8}{s ^{4}} + \frac{1}{s ^{6}}

- \frac{( x + 1 ) ( x - 4 )}{6}

\frac{( x + 4 ) ^{2}}{2}

\frac{4 ( 2 x + 5 y )}{13 x}

\frac{1}{k x ( a - x )}

(12 x^{7} + 9 x^{6} + 4 x^{2} + π) (x - 1)

What is expand ((4s^2-1)^2)/(s^6) ?
The solution to expand ((4s^2-1)^2)/(s^6) is (16)/(s^2)-8/(s^4)+1/(s^6)