What is expand 2/9 (3e^{3x}x-e^{3x})+C ?

The solution to expand 2/9 (3e^{3x}x-e^{3x})+C is (2e^{3x}x)/3-2/9 e^{3x}+C

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expand 2/9 (3e^{3x}x-e^{3x})+C

expand

\frac{2}{9} (3 e^{3 x} x - e^{3 x}) + C

\frac{2 e ^{3 x} x}{3} - \frac{2}{9} e^{3 x} + C

Solution steps

\frac{2}{9} (3 e^{3 x} x - e^{3 x}) + C

Expand

\frac{2}{9} (3 e^{3 x} x - e^{3 x}) : \frac{2 e ^{3 x} x}{3} - \frac{2}{9} e^{3 x}

= \frac{2 e ^{3 x} x}{3} - \frac{2}{9} e^{3 x} + C

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What is expand 2/9 (3e^{3x}x-e^{3x})+C ?
The solution to expand 2/9 (3e^{3x}x-e^{3x})+C is (2e^{3x}x)/3-2/9 e^{3x}+C