What is expand (x^2-3x+6)/(x(x-2)(x-1)) ?

The solution to expand (x^2-3x+6)/(x(x-2)(x-1)) is (x^2-3x+6)/(x^3-3x^2+2x)

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expand (x^2-3x+6)/(x(x-2)(x-1))

expand

\frac{x ^{2} - 3 x + 6}{x ( x - 2 ) ( x - 1 )}

\frac{x ^{2} - 3 x + 6}{x ^{3} - 3 x ^{2} + 2 x}

Solution steps

\frac{x ^{2} - 3 x + 6}{x ( x - 2 ) ( x - 1 )}

Expand

x (x - 2) (x - 1) : x^{3} - 3 x^{2} + 2 x

= \frac{x ^{2} - 3 x + 6}{x ^{3} - 3 x ^{2} + 2 x}

\frac{x ^{4} + 1}{x ^{2}}

(9 - 6 x + x^{2})^{3} \cdot 4

(4 x^{2} + 2 x - 1) (2 x - 1)!

\frac{s + 34}{( s + 5 + 3 j ) ( s + 5 - 3 j )}

(4 - x^{2 \circ} x - 2) (x)

What is expand (x^2-3x+6)/(x(x-2)(x-1)) ?
The solution to expand (x^2-3x+6)/(x(x-2)(x-1)) is (x^2-3x+6)/(x^3-3x^2+2x)