What is expand (2x+7y=1,5)(-5x-7y=11) ?

The solution to expand (2x+7y=1,5)(-5x-7y=11) is -10x^2-14xy=11

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expand (2x+7y=1,5)(-5x-7y=11)

expand

(2 x + 7 y = 1, 5) (- 5 x - 7 y = 11)

- 10 x^{2} - 14 x y = 11

Solution steps

(2 x + 7 y = 1, 5) (- 5 x - 7 y = 11)

= (2 x + 7 \cdot 1 \cdot 5 =, y) (- 5 x - 7 \cdot 11 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = 7 y = 1, 5, c = - 5 x, d = - 7 y = 11

2 x (- 5 x) + 2 x (- 7 y = 11) + 7 y = 1, 5 (- 5 x) + 7 y = 1, 5 (- 7 y = 11)

Apply minus-plus rules

+ (- a) = - a

- 2 \cdot 5 xx - 2 \cdot 7 x y = 11 - 7 y = 1, 5 \cdot 5 x - 7 y = 1, 5 \cdot 7 y = 11

Expand

- 2 \cdot 5 xx - 2 \cdot 7 x y : - 10 x^{2} - 14 x y

- 10 x^{2} - 14 x y = 11

\frac{( x + 2 ) ( y - 1 )}{( x - 3 ) ( y + 1 )}

\frac{x ^{2} + 7 x + 9}{( x + 1 ) ( x - 1 )}

(3 i, - i) (i, 8 i)

(x + 5) \circ (x - 3)

(5 x - 2 y) y^{'} (x) + x - y

What is expand (2x+7y=1,5)(-5x-7y=11) ?
The solution to expand (2x+7y=1,5)(-5x-7y=11) is -10x^2-14xy=11