What is expand (3(2x-x^2))/4 ?

The solution to expand (3(2x-x^2))/4 is -(3x^2)/4+(3x)/2

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expand (3(2x-x^2))/4

expand

\frac{3 ( 2 x - x ^{2} )}{4}

- \frac{3 x ^{2}}{4} + \frac{3 x}{2}

Solution steps

\frac{3 ( 2 x - x ^{2} )}{4}

Expand

3 (2 x - x^{2}) : 6 x - 3 x^{2}

= \frac{6 x - 3 x ^{2}}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x - 3 x ^{2}}{4} = \frac{6 x}{4} - \frac{3 x ^{2}}{4}

= \frac{6 x}{4} - \frac{3 x ^{2}}{4}

Cancel

\frac{6 x}{4} : \frac{3 x}{2}

= \frac{3 x}{2} - \frac{3 x ^{2}}{4}

Rewrite in standard form

= - \frac{3 x ^{2}}{4} + \frac{3 x}{2}

- \frac{2 v}{( 2 x + 1 ) ( v - 1 )}

4 (3 x - y = 4)

(3 x + y = 4,) (- x + 2 y = 15)

f (t - π) H (t - π)

x^{4} (e^{x} x - e^{x} + c)

What is expand (3(2x-x^2))/4 ?
The solution to expand (3(2x-x^2))/4 is -(3x^2)/4+(3x)/2