What is expand f(t-pi)\H(t-pi) ?

The solution to expand f(t-pi)\H(t-pi) is ft\H(t-pi)-pif\H(t-pi)

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expand f(t-pi)\H(t-pi)

expand

f (t - π) H (t - π)

f t H (t - π) - π f H (t - π)

Solution steps

f (t - π) H (t - π)

= f H (t - π) (t - π)

Apply the distributive law:

a (b - c) = ab - a c

a = f H (t - π), b = t, c = π

= f H (t - π) t - f H (t - π) π

= f t H (t - π) - π f H (t - π)

x^{4} (e^{x} x - e^{x} + c)

\frac{d}{d x} ((x) (6 x + 2)^{3})

- π sin (t) cos (t) (u - 1)

- \frac{3 n ^{2} ( n + 1 ) ^{2}}{2}

π (x^{2} + 6 x + 3)^{2}

What is expand f(t-pi)\H(t-pi) ?
The solution to expand f(t-pi)\H(t-pi) is ft\H(t-pi)-pif\H(t-pi)