What is expand (3x+y=4,)(-x+2y=15) ?

The solution to expand (3x+y=4,)(-x+2y=15) is -3x^2+6xy=15

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expand (3x+y=4,)(-x+2y=15)

expand

(3 x + y = 4,) (- x + 2 y = 15)

- 3 x^{2} + 6 x y = 15

Solution steps

(3 x + y = 4,) (- x + 2 y = 15)

= (3 x + 4 =, y) (- x + 2 \cdot 15 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 3 x, b = y = 4,, c = - x, d = 2 y = 15

3 x (- x) + 3 x \cdot 2 y = 15 + y = 4, (- x) + y = 4, 2 y = 15

Apply minus-plus rules

+ (- a) = - a

- 3 xx + 3 \cdot 2 x y = 15 - y = 4, x + y = 4, 2 y = 15

Expand

- 3 xx + 3 \cdot 2 x y : - 3 x^{2} + 6 x y

- 3 x^{2} + 6 x y = 15

f (t - π) H (t - π)

x^{4} (e^{x} x - e^{x} + c)

\frac{d}{d x} ((x) (6 x + 2)^{3})

- π sin (t) cos (t) (u - 1)

- \frac{3 n ^{2} ( n + 1 ) ^{2}}{2}

What is expand (3x+y=4,)(-x+2y=15) ?
The solution to expand (3x+y=4,)(-x+2y=15) is -3x^2+6xy=15